Question
One more problem with 1/2 reactions
Pb(s) + PbO2(s) + 2H2SO4(aq)->2PbSO4(aq)+2H2O(l).
How do you split them up with two Pb solids on the same side of the equation?
Again you need to identify what is being reduced and what is being oxidised.
I think I read the question wrong Im not sure I need to split the reaction. I am trying to calculate delta G given an Ecell of 2.04V. Using Delta G = -nFEcell. I know F and Ecell but I need to find the value of n.
Pb goes from 0 on the left to +2 on the right as PbSO4.
Pb in PbO2 goes from +4 on the left to +2 on the right as PbSO4.
So change in electrons is 2 for n.
Pb(s) + PbO2(s) + 2H2SO4(aq)->2PbSO4(aq)+2H2O(l).
How do you split them up with two Pb solids on the same side of the equation?
Again you need to identify what is being reduced and what is being oxidised.
I think I read the question wrong Im not sure I need to split the reaction. I am trying to calculate delta G given an Ecell of 2.04V. Using Delta G = -nFEcell. I know F and Ecell but I need to find the value of n.
Pb goes from 0 on the left to +2 on the right as PbSO4.
Pb in PbO2 goes from +4 on the left to +2 on the right as PbSO4.
So change in electrons is 2 for n.
Answers
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