Asked by Huzeuf awee
At what angle must a rifle be fired if it is to hit a target at the same level 150 m away dead center? The initial speed of the bullet is 450m/s
Answers
Answered by
bobpursley
time in air: 450cosTheta*time=150
time in air= 1/3cosTheta second
but in the vertical
time in air is found by
hf=hi+vi'*t -4.9t^2 or
t=sqrt(450sinTheta/4.9)
set the two time equal
sqrt(450sinTheta/4.9)=1/3cosTheta
and you have the solution with a little trig. Remember
cos^2 X= 1-sin^2 x ...and the quadratic equation
time in air= 1/3cosTheta second
but in the vertical
time in air is found by
hf=hi+vi'*t -4.9t^2 or
t=sqrt(450sinTheta/4.9)
set the two time equal
sqrt(450sinTheta/4.9)=1/3cosTheta
and you have the solution with a little trig. Remember
cos^2 X= 1-sin^2 x ...and the quadratic equation
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.