Asked by sabina
A 0.774 g
mixture containing only sodium chloride and potassium chloride was dissolved in water. It required 29.6 mL
of 0.416 M AgNO3
to completely precipitate all of the chloride present. What is percent composition by mass of sodium chloride and potassium chloride in the mixture?
mixture containing only sodium chloride and potassium chloride was dissolved in water. It required 29.6 mL
of 0.416 M AgNO3
to completely precipitate all of the chloride present. What is percent composition by mass of sodium chloride and potassium chloride in the mixture?
Answers
Answered by
DrBob222
This requires two equations and they are solved simultaneously.
Let X = mass NaCl and
Let Y = mass KCl
equn 1 is X + Y = 0.774 g
To save typing mm = molar mass then
equn 2 comes from
mols AgCl due to NaCl + mols AgCl due to KCl = total mols AgCl formed
[X(mm AgCl/mm NaCl)] +[Y(mm AgCl/mm KCl)] = MAgNO3*LAgNO3
Solve those two equations simultaneously to obtain X = grams NaCl and Y = grams KCl.
Then %NaCl = (X/mass sample)*100 = ?
%KCL = (Y/mass sample)*100 = ?
Post your work if you get stuck.
Let X = mass NaCl and
Let Y = mass KCl
equn 1 is X + Y = 0.774 g
To save typing mm = molar mass then
equn 2 comes from
mols AgCl due to NaCl + mols AgCl due to KCl = total mols AgCl formed
[X(mm AgCl/mm NaCl)] +[Y(mm AgCl/mm KCl)] = MAgNO3*LAgNO3
Solve those two equations simultaneously to obtain X = grams NaCl and Y = grams KCl.
Then %NaCl = (X/mass sample)*100 = ?
%KCL = (Y/mass sample)*100 = ?
Post your work if you get stuck.