Asked by victor
the first term of a gp is twice its common ratio. find the sum of the first two terms of the progression if its sum to infinity is 8
Answers
Answered by
Reiny
We are told that
a = 2r
sum of all terms = a/(1-r)
2r/(1-r) = 8
2r = 8 - 8r
10r = 8
r = 4/5
then a = 8/5
sum of first two terms = a + ar
= 8/5 + (8/5)(4/5) = 50/5 = 10
check for sum of all terms to be 8
sum(all terms) = (8/5) / (1 - 4/5)
= (8/5) / 1/5)
= 8
a = 2r
sum of all terms = a/(1-r)
2r/(1-r) = 8
2r = 8 - 8r
10r = 8
r = 4/5
then a = 8/5
sum of first two terms = a + ar
= 8/5 + (8/5)(4/5) = 50/5 = 10
check for sum of all terms to be 8
sum(all terms) = (8/5) / (1 - 4/5)
= (8/5) / 1/5)
= 8
Answered by
Anonymous
Is it correct
Answered by
Ofa
The answer is not correct the final answer is 72/25
Answered by
Favor
The answer is very wrong the correct answer is either 72/25 or 2 22/25
Answered by
Lady O
We are told that
a = 2r
sum of all terms = a/(1-r)
2r/(1-r) = 8
2r = 8 - 8r
10r = 8
r = 4/5
then a = 8/5
sum of first two terms = a + ar
= 8/5 + (8/5)(4/5)
=8/5 + 32/25
a = 2r
sum of all terms = a/(1-r)
2r/(1-r) = 8
2r = 8 - 8r
10r = 8
r = 4/5
then a = 8/5
sum of first two terms = a + ar
= 8/5 + (8/5)(4/5)
=8/5 + 32/25
Answered by
Lady O
Final answer =72/25
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