For A, you're right
For B, you're right
For C, it would just be 12/52 because you've only taken 1/52 away and that was a heart.
Two cards are drawn without replacement from a well-shuffled deck of 52 playing cards.
a. What is the probability that the first card drawn is a heart?
b. What is the probability that the second card drawn is a heart if the first card drawn was not a heart?
c.What is the probability that the second card drawn is a heart if the first card drawn was a heart?
I know that there are 13 hearts total.
a. P(1st heart) = 13/52
b. P( 2nd heart l 1st heartcomplement) = 13/51. I guess if one card was drawn on the first attempt, there are 51 remaining but there are still 12 hearts.
c. This one I am a bit unsure of. P(2nd heart l 1st heart) = 13/52 * 12/51?
2 answers
Disagree with AJL on C. If you have already drawn a heart and not replaced it, the probability of a second heart is 12/51.
1 answer