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If 15gram of potassium trioxochlorate V is heated in the presence of MnO2.What is the mass of chloride produce?Asked by Anonymous
If 15g of potassium trioxochlorate(v) is heated in the presence of Mno2. what is the mass of chloride produce
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Answered by
sunny
Potassium trioxochlorate (V) is another name for KClO3. The balanced reaction is
2KClO3(s) + heat �¨ 2KCl(s) + 3O2(g)
------------ (MnO2 catalyst)
15 g of KClO3 is 15g/122.6 g/mol = 0.1224 mol KClO3. You will make the same number of moles of KCl. Multiply that by the molar mass of KCl (74.6 g/mol) for the answer.
I get 9.13 moles
Hope this helped :)
2KClO3(s) + heat �¨ 2KCl(s) + 3O2(g)
------------ (MnO2 catalyst)
15 g of KClO3 is 15g/122.6 g/mol = 0.1224 mol KClO3. You will make the same number of moles of KCl. Multiply that by the molar mass of KCl (74.6 g/mol) for the answer.
I get 9.13 moles
Hope this helped :)
Answered by
DrBob222
Potassium trioxochlorate(v) is not an IUPAC name for KClO3.
Answered by
Mujahid
15g of KCLO3
Molar mass of KCLO3 = 122.55g/mol~122.6g/mol
Number of moles= mass/molar mass
=15/122.6 = 0.1223mol
Multiply by the molar mass of KCL = 74.55~74.6
74.6×0.1223= 9.12g
Your mistakes were in the calculation of 15/122.6 and the unit of your final answer which is supposed to be in grams
I.e g/mol ×mol
Molar mass of KCLO3 = 122.55g/mol~122.6g/mol
Number of moles= mass/molar mass
=15/122.6 = 0.1223mol
Multiply by the molar mass of KCL = 74.55~74.6
74.6×0.1223= 9.12g
Your mistakes were in the calculation of 15/122.6 and the unit of your final answer which is supposed to be in grams
I.e g/mol ×mol
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