Asked by Etinosa
Given that √6,3√2,3√6,9√2 ...are the first 4 terms of an exponential sequence. Find in it
simplest form the 8term
simplest form the 8term
Answers
Answered by
Reiny
looks like you have a = √6
and
ar = 3√2
r = 3√2/√6 = 3/√3 = 3/√3 * √3/√3 = √3
term(8) = ar^7
= √6(√3)^7
= √6(√3)^6 (√3)
= √18 * 27
= 81√2
and
ar = 3√2
r = 3√2/√6 = 3/√3 = 3/√3 * √3/√3 = √3
term(8) = ar^7
= √6(√3)^7
= √6(√3)^6 (√3)
= √18 * 27
= 81√2
Answered by
ni
procedures on how to solve this solution
Answered by
Victor
Thanks
Answered by
Victor
Can you teach me pls
Answered by
Victor
Ans=81√2
That's the right answer
That's the right answer
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