What is the minimum amount of 6.3 M H2SO4 necessary to produce 27.7 g of H2 (g) according to the following reaction?

Question

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

Answer 1

mols H2 needed = grams/molar mass =( 27.7/2) = 13.85
Convert mols H2 to mols H2SO4 this way:
13.35 mols H2 x (3 mols H2SO4/3 mols H2) = 13.35 mols H2SO4,
Then M H2SO4 = mols H2SO4/L H2SO4.
Yu know mols and M, solve for L. Convert to mL if needed.