The probability a car salesman sells a car to a customer is 0.05 Assuming the salesmen sees 14 customers in a week, what is the probability he sells less than 2 cars?

Answer 1

prob(sell car) = .05
prob(not sell car) = .95

Prob(less than 2 cars)
= prob(sell no car) + prob(sell 1 car)
= C(14,0) (.05)^0 (.95)^14 + C(14,1) (.05)^1 (.95)^13
= ...
let me know what you get

Answer 2

0.153