Question
Eddie and his sister walked from home to school. His sister started walking at 8:00am at an average speed of 50 m/min. Eddie started walking at 8:05 at a speed of 60 m/min. Eddie caught up with his sister at mid-point between the school and his home. Find the distance between Eddie's home and the school.
Please help, thank you so much
Please help, thank you so much
Answers
Let the distance between home and school be 2x
So they met after x metres.
Sister went for t minutes at 50 m/min , so x = 50t
Eddie went for (t-5) minutes at 60 m/min so x = 60(t-5)
but those are equal, so
60(t-5) = 50t
60t - 300 = 50t
t = 30
then x = 50(30) m = 1500 m
and the school is 3000 m or 3 km from home
So they met after x metres.
Sister went for t minutes at 50 m/min , so x = 50t
Eddie went for (t-5) minutes at 60 m/min so x = 60(t-5)
but those are equal, so
60(t-5) = 50t
60t - 300 = 50t
t = 30
then x = 50(30) m = 1500 m
and the school is 3000 m or 3 km from home
Got it. Thanks
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