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What is the domain and range of f-1(x) = -6 + or - squareroot of x+75/2
5 years ago

Answers

oobleck
If f^-1(x) = (-6±√75)/2 then f(x) = 4x^2+24x-39 = 4(x+3)^2 - 75
so the domain is all reals
and the range is all reals >= -75

technically, f(x) = a(4(x+3)^2 - 75) so the range is y >= -75/a
5 years ago

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