Asked by Samama

The ratio of the legs of a right triangle is 19:28. Find the measurements of its angles.
Answered by oobleck
one of the angles is θ, such that
tanθ = 19/28
The other angle is 90°-θ
Answered by henry2,
19x + 28x = 90.
X = 1.915.
19x = 36.38o.
28x = 53.62o.
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