One strategy in a snowball fight is to throw

Question

a snowball at a high angle over level ground.
While your opponent is watching this first
snowball, you throw a second snowball at a
low angle and time it to arrive at the same
time as the first.
Assume both snowballs are thrown with
the same initial speed 13.4 m/s. The first
snowball is thrown at an angle of 53◦
above
the horizontal. At what angle should you
throw the second snowball to make it hit the
same point as the first? The acceleration of
gravity is 9.8 m/s
2
.
Answer in units of ◦

Answer 1

answer: 19 degrees

explanation:
when i write v0 it means v initial

distance traveled by snowball 1

d1 = v0t1 = (v*cos(theta1)) * [ (2v0*sin(theta1)) / (g) ]
since sin(2(theta)) is 2sin(theta)cos(theta)
d1 = ((v0)^2 / g)*sin2(theta1)

for the same reason,
d2 = ((v0)^2 / g)*sin2(theta2)

set d1 equal to d2 and solve for theta2 with calculator or with trig identities