Asked by Ajani huff

Pothagorem therom
Determine the missing measurements for each TV.

32” TV height: 16” width: _____




• _____ TV height: 34” width: 61”




• 60” TV height: 30” width: _____




• _____ TV height: 20” width: 35”




• 52” TV height: _____ width: 45”


If a TV has the following dimensions 48” wide, 27” height, and 55”diagonal. Respond to the following questions.


If the TV is 5” wider and 3” higher, what is the new diagonal measurement? (Show work)




 If the TV is 3” wider and 5” higher, what is the new diagonal measurement? (Show work)
Answered by Reiny
In all your cases, it appears that TV represents the diagonal of the television.

In all cases, PYTHAGORAS, (notice the spelling), says

TV^2 = height^2 + width^2

just insert the 2 given data values, and solve for the missing one

I will do one, you do the others in the same way:
• 60” TV height: 30” width: _____
TV^2 = height^2 + width^2
60^2 = 30^2 + width^2
3600 = 900 + width^2
2700 = width^2
width^2 = √2700 = appr 52 inches
Answered by Mijg Mijg
Im confused?
Answer
wth. y did they have to complicate something so simple. idiots
Answer
JUST ANSWER THE F'ING QUESTION!!!!!!!
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