Asked by dom
Elisha thought that (2x+1) was a factor of p(x). She evaluated p(−1) and didn't get 0. Based on her work, what can Elisha conclude?
Elisha can conclude that (2x+1) is not a factor of p(x). The Factor Theorem states that (2x+1) is only a factor of p(x) if p(−1)=0. Since she didn't get 0 when she evaluated, it must not be a factor.
Elisha can't conclude whether (2x+1) is a factor because she evaluated the wrong x value. She needed to evaluate p(−1/2) instead. If p(−1/2)=0, then (2x+1) is a factor of p(x).
Elisha can conclude that (2x+1) is a factor of p(x). The Factor Theorem states that (2x+1) is a factor of p(x) if p(−1)≠0. Since she didn't get 0 when she evaluated, it must be a factor.
Elisha can't conclude whether (2x+1) is a factor because she evaluated the wrong x value. She needed to evaluate p(1) instead. If p(1)=0, then (2x+1) is a factor of p(x).
Answers
Answered by
dom
is it a
Answered by
dom
is it C
Answered by
Reiny
Wrong and Wrong
You can either keep guessing or learn all about the Factor Theorem so you can answer this question without guessing.
From what you said, my conclusion would be that x+1 is not a factor
You can either keep guessing or learn all about the Factor Theorem so you can answer this question without guessing.
From what you said, my conclusion would be that x+1 is not a factor
Answered by
uwu
Elisha can't conclude whether (2x+1) is a factor because she evaluated the wrong x value. She needed to evaluate p(−1/2) instead. If p(−1/2)=0, then (2x+1) is a factor of p(x).
hope this help! <3
hope this help! <3
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