Asked by LARA

Joyce had some money. She bought a dress, a shirt and a watch. She spent 1/5 of her money on a shirt. The shirt cost $24 less than a dress. The watch cost $102. She was left with 1/4 of the amount of money she had at first. How much money did Joyce have at first?

Please help!!!!
Answered by Reiny
amount of money she had at first ---- x

cost of shirt ------ x/5
"The shirt cost $24 less than a dress" ----> the dress cost 24 more than the shirt ------ x/5 + 24

shirt + dress + watch = (3/4)x,
(if 1/4 of her money is left, she must have spent 3/4 of it)

x/5 + x/5+24 + 102 = 3x/4
multiply each term by 20, to clear the fractions
4x + 4x + 480 + 2040 = 15x

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