Asked by Spencer

Dr. Pepper left Oakville at 9:00 AM and drove to Central City at 60 km/h. H. Salt left Oakville at 11:00 AM and traveled the same route to Central City. If both men arrived at Central City by 4:00 PM at what rate did H Salt travel. We have to set the questions up as d=rt and im not sure how I would set it up. Would I do 7(x)=5(x-2)?
Answered by oobleck
Not quite. x and x-2 are the time needed. You already have that. You want the speed. So,
7*60 = 5x

You have multiplied time * time, rather than time * speed.
Answered by Reiny
No
First of all you have to define what x is.

let x be the speed of H Salt
they went the same distance, which we can find
Pepper went 7 hrs at 60 km/h , so the distance is 420 km
Salt did the same trip in 5 hours
so 5x = 420
x = 84
So H Salt went at 84 km/h


your equation would solve to
7x = 5x - 10
2x = -10
x = -5
clearly a meaningless result.
What was that equation supposed to say?
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