Question

this is a repost.

What is the change in enthalpy for magnesium after the reaction with vinegar?
vinegar is 60ml
magnesium is 0.7g
T1 = ?
T2 = 31.8°C
find the initial temperature if 123.4 KJ energy has been released.

Mg + 2HC2H3O2 ==> Mg(C2H3O2)2 + H2
1 mole of mg is 24.31g
mols Mg = 0.7/24.3 = about 0.0288

q = mass soln x specific heat soln x (Tfinal-Tinitial)
-123400 J = 60 g x 4.184 J/oC*g x (31.8 - Ti)

I really don't know how to solve for Ti. can someone help me!