Asked by Sarah Banks
0.499g of Cuso.XH2O when heated to constant weight gave a residue 0.34g The value of X is?
Answers
Answered by
bobpursley
moles of water=(.499-.34)/18=.0088
moles of CuSO4=(.34)/160=.0021
ratio=.0088/.0021=4.2
X=4 work it out more accurately.
moles of CuSO4=(.34)/160=.0021
ratio=.0088/.0021=4.2
X=4 work it out more accurately.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.