Question
0.499g of Cuso.XH2O when heated to constant weight gave a residue 0.34g The value of X is?
Answers
bobpursley
moles of water=(.499-.34)/18=.0088
moles of CuSO4=(.34)/160=.0021
ratio=.0088/.0021=4.2
X=4 work it out more accurately.
moles of CuSO4=(.34)/160=.0021
ratio=.0088/.0021=4.2
X=4 work it out more accurately.