Question
the nth term of a sequence is log(n +3) to base 2. what is the difference between the 13th term and the first term?
Answers
Reiny
term(n) = log<sub>2</sub>(n+3)
term(13) = log<sub>2</sub>(16)
term(1) = log<sub>2</sub>(4)
difference = log<sub>2</sub>16 - log<sub>2</sub>4
= log<sub>2</sub>(16/4)
= log<sub>2</sub> 4
= 2
term(13) = log<sub>2</sub>(16)
term(1) = log<sub>2</sub>(4)
difference = log<sub>2</sub>16 - log<sub>2</sub>4
= log<sub>2</sub>(16/4)
= log<sub>2</sub> 4
= 2
Charity
That's not my question