Asked by Faria

The electrons that produce the picture in a TV set are accelerated by a very large electric force as they pass through a small region in the neck of the picture tube. This region is 1.6 cm in length, and the electrons enter with a speed of 1 × 105 m/s and leave with a speed of 2.5 × 106 m/s.
What is their acceleration over this 1.6 cm length?
Answer in units of m/s2.

How long is the electron in the accelerating region?
Answer in units of s.
Answered by henry2,
d = V*t = 0.016.
1*10^5t = 0.016,
t = 1.6*10^-7 s.

V = Vo + a*t = 2.5*10^6.
1*10^5 + a*1.6*10^-7 = 2.5*10^6.
a =
Answered by Faria
would a be 1.5*10^13?
Answered by henry2,
My ans. is 1.446*10^13.
Answered by R_scott
average velocity is ... (1E5 + 2.5E6) / 2 = 1.3E6 m/s

transit time is ... t = d / v = 1.6E-2 m / 1.3E6 m/s = 1.2E-8 s

acceleration is ... (2.5E6 - 1E5) / 1.2E-8 = 2.0E14 m/s^2