Question

A sample of phosphorus-32 has a half-life of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 days, what was the mass of the original sample?

help please, im confused.

Answer 1

First, use the half life to calculate k.
k = 0.693/half life = ?
Then ln (No/N) = kt
No = solve for this
N = 55 g
you know k from above
t = 57 days (the problem says APPROXIMATELY 57 days. What kind of double talk is this? How many days is it really.
Post your work if you get stuck.

Answer 2

boomer burger