Asked by hipniblet
A sample of phosphorus-32 has a half-life of 14.28 days. If 55 g of this radioisotope remain unchanged after approximately 57 days, what was the mass of the original sample?
help please, im confused.
help please, im confused.
Answers
Answered by
DrBob222
First, use the half life to calculate k.
k = 0.693/half life = ?
Then ln (No/N) = kt
No = solve for this
N = 55 g
you know k from above
t = 57 days (the problem says APPROXIMATELY 57 days. What kind of double talk is this? How many days is it really.
Post your work if you get stuck.
k = 0.693/half life = ?
Then ln (No/N) = kt
No = solve for this
N = 55 g
you know k from above
t = 57 days (the problem says APPROXIMATELY 57 days. What kind of double talk is this? How many days is it really.
Post your work if you get stuck.
Answered by
unhelpful boomer
boomer burger
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