Asked by kevin
solve:2y^2+8y-24=0
Answers
Answered by
Anonymosu
2y<sup>2</sup> + 8y - 24 = 0
2(y<sup>2</sup> + 4y - 12) = 0
2(y + 6)(y - 2) = 0
(y + 6) = 0
(y - 2) = 0
y = -6
y = 2
2(y<sup>2</sup> + 4y - 12) = 0
2(y + 6)(y - 2) = 0
(y + 6) = 0
(y - 2) = 0
y = -6
y = 2
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