Question
If 0.790 mol of solid TiO2 and 8.53 g of solid C are reacted stoichiometrically according to the balanced equation, how many moles of solid TiO2 remain?
3TiO2(s) + 4C(s) + 6Cl2(g) → 3TiCl4(l) + 2CO2(g) + 2CO(g)
3TiO2(s) + 4C(s) + 6Cl2(g) → 3TiCl4(l) + 2CO2(g) + 2CO(g)
Answers
Change C to moles.
8.53 g/12.01 = ?? mols
Now convert moles TiO2 to moles of any one of the products, say TiCl4.
Convert moles C to moles TiCl4.
That will give you the limiting reagent; either TiO2 or C.
Using the limiting reagent (which I assume will be C), convert moles C to moles TiO2 and subtract from the initial moles of TiO2 to find the amount of TiO2 remaining after reaction.
8.53 g/12.01 = ?? mols
Now convert moles TiO2 to moles of any one of the products, say TiCl4.
Convert moles C to moles TiCl4.
That will give you the limiting reagent; either TiO2 or C.
Using the limiting reagent (which I assume will be C), convert moles C to moles TiO2 and subtract from the initial moles of TiO2 to find the amount of TiO2 remaining after reaction.
Related Questions
If 0.110 mol of liquid H2O and 40.5 g of solid Al2S3 are reacted stoichiometrically according to the...
How many grams of gaseous required?
If 0.260 mol of solid C and 20.0 g of solid TiO2 are reacted...
If 4.32 g of solid C reacts stoichiometrically according to the balanced equation, how many grams of...
If 0.760 mol of solid TiO2 and 4.20 g of solid C are reacted stoichiometrically according to the ba...