Asked by jay
An airplane touches down on the runway with a speed of 70 m/s. It decelerates at a rate of -5 m/s2.
Answers
Answered by
Anonymous
v = Vi + a t
Vi = 70 given
a =-5 given
so
v = 70 - 5 t
note: not 70 - (-5t)
Vi = 70 given
a =-5 given
so
v = 70 - 5 t
note: not 70 - (-5t)
Answered by
Reiny
a = -5 m/s^2
v = (-5t + k) m/s
when t = 0 , v = 70 m/s
70 = 0 + k ----> k = 70
v = (-5t + 70) m/s
now you can find the velocity at any time after touchdown
but you asked no question.
If the question was, "how long before the plane stops ?" , then
solve
-5t + 70 = 0 for t
v = (-5t + k) m/s
when t = 0 , v = 70 m/s
70 = 0 + k ----> k = 70
v = (-5t + 70) m/s
now you can find the velocity at any time after touchdown
but you asked no question.
If the question was, "how long before the plane stops ?" , then
solve
-5t + 70 = 0 for t
Answered by
cherry
v = vi + at
vi = 70 given
a = -5 given so that determines that
v = 70 - 5t
note:it is not 70 - (-5t)
If you write this down you teacher will not be disappointed, mine wasn’t.
vi = 70 given
a = -5 given so that determines that
v = 70 - 5t
note:it is not 70 - (-5t)
If you write this down you teacher will not be disappointed, mine wasn’t.
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