arc length s = rθ
so, the perimeter of ABC is 2r+rθ = 2*3 + 3*(35/360)(2π)
Not quite sure what O has to do with it. Maybe there is more that I have not discerned, and you can finish it up.
I have assumed that the central angle C is 35°. Rereading the post, I have some doubts about that. Is ABC just some arbitrary triangle? Is AB an arc of the circle with center at O? But you say O is on the line? arc? AB.
Given: ∆ABC, m∠A = 35°
Circle k(O, r=3)
O∈ AB
Find: Perimeter of ∆ABC
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3 answers