The current in a 62-Ω resistor is 0.15 A. This resistor is in series with a 25-Ω resistor, and the series combination is connected across a battery. What is the battery voltage?

I will be happy to critique your thinking.

To find the battery voltage, we can use Ohm's Law, which states that V = I * R, where V is the voltage, I is the current, and R is the resistance.

In this case, we have two resistors in series, so the total resistance (RT) is the sum of the individual resistances (R1 and R2):
RT = R1 + R2

Given:
R1 = 62 Ω
R2 = 25 Ω
I = 0.15 A

Substituting the values into the equation, we have:
RT = 62 Ω + 25 Ω
RT = 87 Ω

Now we can calculate the battery voltage:
V = I * RT
V = 0.15 A * 87 Ω
V = 13.05 V

Therefore, the battery voltage is 13.05 volts.

To find the battery voltage, we need to use Ohm's Law, which states that voltage is equal to the product of current and resistance.

In this case, we have the current (0.15 A) and the total resistance (62 Ω + 25 Ω = 87 Ω). We can use these values to find the battery voltage.

The formula for Ohm's Law is:

V = I * R

where V is the voltage, I is the current, and R is the resistance.

Plug in the given values:

V = 0.15 A * 87 Ω

Now, multiply the current and resistance:

V = 13.05 V

The battery voltage is 13.05 volts.