You throw a water balloon hoping to hit your sibling. You throw it at an angle of 28.0° at 9.60 m/s. It ends up leaving your hand at a height of 2.00 m above the ground. It completely misses your sibling and breaks on the ground. How far did the water balloon travel?

Answer 1

The height y = 2 + (9.6 sin28°)t - 4.9t^2
find when y=0, then use that t to find the distance
x = 9.6 cos28° * t