Asked by JAY_ndabeh
A reaction between A and B is found to be first order in [A] and second order in [B]. If [A] is halved and [B] is doubled, the rate of the reaction will
(A) remain the same.
(B) be increased by a factor of 2.
(C) be increased by a factor of 4.
(D) be increased by a factor of 8.
I think the answer is A because I suspect that
The 1/2 and the double will cancel each other
Rate=k([A]/2).([B]exp2)x2
(A) remain the same.
(B) be increased by a factor of 2.
(C) be increased by a factor of 4.
(D) be increased by a factor of 8.
I think the answer is A because I suspect that
The 1/2 and the double will cancel each other
Rate=k([A]/2).([B]exp2)x2
Answers
Answered by
DrBob222
A is not right but your equation is correct. Just do the math.
[A]^1 x [B]^2.
A = 1/2 = 1/2 ^1 = 1/2
B = x2 and 2x2 = 4
so 1/2 x 4 = ?
[A]^1 x [B]^2.
A = 1/2 = 1/2 ^1 = 1/2
B = x2 and 2x2 = 4
so 1/2 x 4 = ?
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