you know that sin30 = 1/2
Use that as a reference angle
where else is sinx > 0 ?
1. Given that sin x =0.5 find the value of x between 90 and 360
3 answers
sin x = 0.5. X = 30o N. of E. = 30o CCW.
sin x = 0.5. X = 30o N. of W. = 150o CCW.
sin x = 0.5. X = 30o N. of W. = 150o CCW.
solve it