Asked by Aries
                1 Given that sin x=0.5,find the values of x between 90° and 360° with solving
2 solve (x-2)(x-3)=12
            
        2 solve (x-2)(x-3)=12
Answers
                    Answered by
            oobleck
            
    you know that sin30° = 1/2
Use that as your reference angle and recall where sinx > 0
(x-2)(x-3) = 12
well, 4*3 = 12, right?
so, x=6
also, -3 * -4 = 12
so, x = -1
Or, if you must,
x^2-5x+6 = 12
x^2-5x-6 = 0
(x-6)(x+1) = 0
    
Use that as your reference angle and recall where sinx > 0
(x-2)(x-3) = 12
well, 4*3 = 12, right?
so, x=6
also, -3 * -4 = 12
so, x = -1
Or, if you must,
x^2-5x+6 = 12
x^2-5x-6 = 0
(x-6)(x+1) = 0
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.