howmany number of gold atoms are present in 0.6 of 18 carat gold. 24 carat gold is taken as 100 % pure gold

0.6 of what? grams? pounds? kg? mg?

To find the number of gold atoms in 0.6 grams of 18-carat gold, you need to follow these steps:

Step 1: Determine the purity of 18-carat gold.
18-carat gold is an alloy composed of 75% gold and 25% other metals like copper or silver. This means that 0.6 grams of 18-carat gold contains 0.6 * 75% = 0.45 grams of pure gold.

Step 2: Convert the weight of pure gold to moles.
To do this, you need to use the molar mass of gold, which is 197 grams/mol. Divide the weight of pure gold by the molar mass to get the number of moles. So, 0.45 grams of pure gold is equal to 0.45 / 197 = 0.002286 moles of gold.

Step 3: Calculate the number of gold atoms.
One mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23. Multiply the number of moles of gold by Avogadro's number to calculate the number of gold atoms. In this case, 0.002286 moles * 6.022 x 10^23 = 1.376 x 10^21 gold atoms.

Therefore, there are approximately 1.376 x 10^21 gold atoms in 0.6 grams of 18-carat gold.