Asked by Anonymous

The volume of air contained in the lungs of a certain athlete is modeled by the equation v=447sin(76πt)+721, where t is time in minutes, and v is volume in cubic centimeters.

What is the maximum possible volume of air in the athlete's lungs?
What is the minimum possible volume of air in the athlete's lungs?
How many breaths does the athlete take per minute?

ive tried this 3 times now and cant seem to get it

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Answered by Anonymous
nevermind I got it!!!!11
Answered by Anonymous
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