Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A small lead ball of mass 2kg is suspended at the end of a light string 1m in length. A small peg, 0.5m below the suspension po...Asked by Habib
A small lead ball of mass 2kg is suspended at the end of a light string 1m in length. A small peg, 0.5m below the suspension point, catches the string in its swing. The ball is set swinging through small angles.
A) What is the period of the pendulum?
B) The ball has started swinging on the side that does not catch the peg, at an initial height 0.05m above the low point. How high does it rise on the side where the peg restricts the pendulum length to 0.5m?
A) What is the period of the pendulum?
B) The ball has started swinging on the side that does not catch the peg, at an initial height 0.05m above the low point. How high does it rise on the side where the peg restricts the pendulum length to 0.5m?
Answers
Answered by
bobpursley
Period now consists of two "half" periods. You know the length of both halves (T=2pi sqrt (L/g) ) Add both periods for each of the lengths, and divide by 2.
for the height, KE will be zero. Initial PE= final PE. Solve for final height from that.
for the height, KE will be zero. Initial PE= final PE. Solve for final height from that.
Answered by
Habib
Can you please detail?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.