Asked by heli
molly traveled to the lake and back.It took two hours less time to get there then it did to get back.The average speed on the trip there was 50 mph.The average speed on the way back was 30 mph.How many hours didthe trip there take?
Answers
Answered by
henry2,
To lake : V1 = 50 mi/h, T1 = X hours.
From lake: V2 = 30 mi/h, T2 = x+2 hours.
d1 = d2.
50*x = 30(x+2).
50x = 30x+60,
X = 3 hours.
From lake: V2 = 30 mi/h, T2 = x+2 hours.
d1 = d2.
50*x = 30(x+2).
50x = 30x+60,
X = 3 hours.
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