Asked by Akinola
calculate the numbers of mole of Cacl2 that can be obtained from 25g of limestone Caco3 in the presence (Ca:40 C:12 O:16 Cl35.5)
Answers
Answered by
DrBob222
in the presence of what?
If CaCO3 is heated you can get
CaCO3 ==> CaO + CO2 so for every mole CaCO3 you start with you can get 1 mole of CaO and whatever that reacts with you can get 1 mol of CaCl2.
So mols CaCO3 in 25 g CaCO3 = 25/molar mass CaCO3 = 25/100 = 0.25. Therefore you can obtain 0.25 mol CaCl2.
If CaCO3 is heated you can get
CaCO3 ==> CaO + CO2 so for every mole CaCO3 you start with you can get 1 mole of CaO and whatever that reacts with you can get 1 mol of CaCl2.
So mols CaCO3 in 25 g CaCO3 = 25/molar mass CaCO3 = 25/100 = 0.25. Therefore you can obtain 0.25 mol CaCl2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.