Asked by Tay
Find (g•f)(x) when f(x)=√x+1 and g(x)= x^2+3/x
A. (g*f)(x)=x+4/sqrt x+1
B. (g*f)(x)=x^2+2x+4/sqrt x+1
C. (g*f)(x)= (x^2+3)(sqrt x+1)/x
D. (g*f)(x)=sqrt x^2+3/x +1
I think its A or B...I'm not sure.
A. (g*f)(x)=x+4/sqrt x+1
B. (g*f)(x)=x^2+2x+4/sqrt x+1
C. (g*f)(x)= (x^2+3)(sqrt x+1)/x
D. (g*f)(x)=sqrt x^2+3/x +1
I think its A or B...I'm not sure.
Answers
Answered by
Reiny
You will have to be sure.
Here is a method you can follow and you will always get it right:
(g•f)(x) = g(f(x))
now f(x) = √x+1 , so replace it is g(f(x))
g(√x + 1) , now note that g(x) = x^2+3/x , so we have to replace the x with x^2+3/x
g(f(x)) = (√x + 1)^2 + 3/(√x + 1)
which does not simplify to any of the choices, so ....
I think you left out some brackets, and it could have been
f(x) = √(x+1)
if so ...
g(f(x))
= g(√(x+1) )
= √(x+1)^2 + 3/√(x+1)
= x+1 + 3/√(x+1)
not a choice either
was it g(x) = (x^2+3)/x , I will not keep guessing
check your typing and repost.
can you see how important these brackets are ?
Here is a method you can follow and you will always get it right:
(g•f)(x) = g(f(x))
now f(x) = √x+1 , so replace it is g(f(x))
g(√x + 1) , now note that g(x) = x^2+3/x , so we have to replace the x with x^2+3/x
g(f(x)) = (√x + 1)^2 + 3/(√x + 1)
which does not simplify to any of the choices, so ....
I think you left out some brackets, and it could have been
f(x) = √(x+1)
if so ...
g(f(x))
= g(√(x+1) )
= √(x+1)^2 + 3/√(x+1)
= x+1 + 3/√(x+1)
not a choice either
was it g(x) = (x^2+3)/x , I will not keep guessing
check your typing and repost.
can you see how important these brackets are ?
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