For the first question regarding the equation \( y = 2.5x - 2 \), we need to check each ordered pair to see if it satisfies the equation:
-
For (-2, 0): \[ y = 2.5(-2) - 2 = -5 - 2 = -7 \quad \text{(not a solution)} \]
-
For (2, 5): \[ y = 2.5(2) - 2 = 5 - 2 = 3 \quad \text{(not a solution)} \]
-
For (2, 3): \[ y = 2.5(2) - 2 = 5 - 2 = 3 \quad \text{(this is a solution)} \]
Thus, the ordered pair that is a part of the solution set is (2, 3).
For the second question about cheerleading tryouts, we need to choose a distribution of cheerleaders that adds up to 12 and is reasonable.
-
8 varsity and 4 junior varsity: This adds up to \(8 + 4 = 12\) (reasonable).
-
0 varsity and 12 junior varsity: This adds up to \(0 + 12 = 12\) (reasonable).
-
15 varsity and -3 junior varsity: This is not reasonable since you cannot have a negative number of cheerleaders.
-
8 varsity and 8 junior varsity: This adds up to \(8 + 8 = 16\) (not reasonable).
Therefore, both 8 varsity cheerleaders and 4 junior varsity cheerleaders and 0 varsity cheerleaders and 12 junior varsity cheerleaders are reasonable solutions. If only one choice is allowed based on the given answers, the best answer is 8 varsity cheerleaders and 4 junior varsity cheerleaders.
Let me know if you need further assistance!
2 answers