let Ms be mass silver, and Vs the volume.
let Mg, Vg be the mass and volume for gold
a. Ms+Mg=9.30
b. Vs+Vg=.650
given Mg/Vg=19.3 and Ms/Vs=10.5
so we can change equation b to read
c. Ms/10.5 + Mg/19.3=.650
so with equation a, and c, you have two equations, two unknowns, I assume you can solve it. Here is the change of c to solve for ms
c'. Ms+ Mg*10.5/19.3=.650*10.5
subtract c' from a, solve for Mg.
final percentage of gold is Mg/(Ms+Mg) * 100
Consider a piece of gold jewelry that weighs 9.30 g and has a volume of 0.650 cm^3 . The jewelry contains only gold and silver, which have densities of 19.3 g/cm3 and 10.5 g/cm3, respectively. If the total volume of the jewelry is the sum of the volumes of the gold and silver that it contains, calculate the percentage of gold (by mass) in the jewelry.
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