Asked by Hannah

What is the value of ddx[f−1(x)] when x=2π, given that f(x)=2x−sinx and f−1(2π)=π ?

I got 1/3 is that right?
Answered by oobleck
If g(x) is f^-1(x), and if f(a) = b, then
g'(b) = 1/f'(a)
so, yes, you are correct
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