Asked by Mandy
Hi,
We did an experiment in lab and our professor asked us why we used acetic acid as our oxidizing agent
NaOCl + CH3COOH --> HOCl + CH3COO- Na+
for the above reaction?
I'm thinking it has to do with the fact that it is a relatively weak acid and can be reversed if needed?
Am I like totally off?
Thanks for any help!
Best,
Mandy
We did an experiment in lab and our professor asked us why we used acetic acid as our oxidizing agent
NaOCl + CH3COOH --> HOCl + CH3COO- Na+
for the above reaction?
I'm thinking it has to do with the fact that it is a relatively weak acid and can be reversed if needed?
Am I like totally off?
Thanks for any help!
Best,
Mandy
Answers
Answered by
DrBob222
I don't see any oxidizing or reducing going on. What you have written is a double displacement reaction (or double replacement reaction).
Answered by
DrBob222
You do have an oxidizing agent in the reaction (NaOCl) BUT it isn't oxidizing anything.
Answered by
Dr Russ
I am not aware of acetic acid being used as an oxidising agent. The peracid is much more common.
So
NaOCl + CH3COOH --> NaCl + CH3COOOH
and the acetic acid is the reducing agent.
Formic acid is used as a reducing agent in Eschweiler-Clarke Methylation.
So
NaOCl + CH3COOH --> NaCl + CH3COOOH
and the acetic acid is the reducing agent.
Formic acid is used as a reducing agent in Eschweiler-Clarke Methylation.
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