Asked by student #1
Wilfred and Wendy have a long distance bike race. Wilfred rides at 20km/h and has a 2 hour head start. Wendy travels at 28 km’h. How long does it take for Wendy to catch up to Wilfred?
To work this problem out, use algebraic form.
To work this problem out, use algebraic form.
Answers
Answered by
R_scott
t is the time to catch up (Wendy's time)
... she catches up when they have traveled the same distance
... his travel time is two hours longer
20 * (t + 2) = 28 * t
... she catches up when they have traveled the same distance
... his travel time is two hours longer
20 * (t + 2) = 28 * t
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