Asked by Vinah

Find the value of x given that
Log(15-5x)-1 log(3x-2)
Answered by Leo
Seems incomplete. Should there be an equals sign somewhere?

Also, if you could post your work for your questions, that would help us help you.
Answered by oobleck
assuming that you meant
log(15-5x)-1 = log(3x-2)
then recall that log10 = 1, so that's the same as
log ((15-5x)/10) = log (3x-2)
if the logs are the same, so are the numbers:
(15-5x)/10 = 3x-2
and you can finish it up.
Answered by henry2,
Log(15-5x) - 1 = Log(3x-2).
Log(15-5x) - Log(3x-2) = 1,
Recall that Log A - Log B = Log(A/B)
Log((15-5x)/(3x-2)) = 1, Log10 = 1
Therefore, (15-5x)/(3x-2) = 10,
15-5x = 30x-20,
X =
Answered by Yvonne
X=1
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