Asked by Hannah

What is the standard form of;
y=√2x-x^2
Answered by oobleck
I assume you mean
y =√(2x-x^2)
so,
y^2 = 2x-x^2
x^2-2x + y^2 = 0
x^2-2x+1 + y^2 = 0+1
(x-1)^2 + y^2 = 1
Answered by Hannah
I'm so sorry i've made a typo wht I mean is y=√25-x^2
Answered by henry2,
y = sqrt(25-x^2).
y^2 = 25 - x^2,
x^2 + y^2 = 25.
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