Asked by Kriti pandey
Calculate the mass of displaced water when a piece of 30 cm thick iceberg with surface area 1000cm^2 floats on water
Given(density of ice=0.9g/cm^3 &density of water=1gm/cm^3
Given(density of ice=0.9g/cm^3 &density of water=1gm/cm^3
Answers
Answered by
henry2,
Vi = As * h = 1000 * 30 = 30,000 cm^3 = Vol. of the ice.
Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.
27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.
Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.
27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.
Answered by
Chand
Best Answer, But You have to improve in writing line by line. Which help us in better Understanding.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.