Asked by jackie
calculate the volume of Nitrogen gas generated at 21 degree celcius and 823 mmHg by the decomposition of 60.0 grams of sodium nitrate?
Answers
Answered by
DrBob222
Heating NaNO3 produces O2 and not N2. Did you mean N2? If so, then
2NaNO3 ==> 2NaNO2 + O2
mols NaNO3 = grams NaNO3/molar mass = 60/approx 85 = about 0.7
Since 2 mol NaNO3 will produce 1 mol O2, then 0.7 mol NaNO3 will produce 0.7/2 = approx 0.35 mol O2.
Then use PV = nRT so solve for the volume.
NOTE: I have estimated all of the numbers. They are close. You need to do them more accurately. Post your work if you have trouble.
2NaNO3 ==> 2NaNO2 + O2
mols NaNO3 = grams NaNO3/molar mass = 60/approx 85 = about 0.7
Since 2 mol NaNO3 will produce 1 mol O2, then 0.7 mol NaNO3 will produce 0.7/2 = approx 0.35 mol O2.
Then use PV = nRT so solve for the volume.
NOTE: I have estimated all of the numbers. They are close. You need to do them more accurately. Post your work if you have trouble.
Answered by
bobpursley
That was my comment also: what do you mean by decomposition? real world, or some fake chemical decomposition given as a teacher thinking problem. Sodium nitrite is very stable, and it (to my knowledge) does not decompose.
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