Question
Given the coordinates of a triangle, A (-3,-4), B (5,-2), C (-5,6)
1. Find the midpoints of each side of the triangle
2. Find the distances of each of the medians of the triangle (the line segment joining the vertex of a triangle and the midpoint of the opposite side)
1. Find the midpoints of each side of the triangle
2. Find the distances of each of the medians of the triangle (the line segment joining the vertex of a triangle and the midpoint of the opposite side)
Answers
oobleck
The midpoint of each line segment is the average of its endpoints.
M(AB) = (A+B)/2 = ((-3+5)/2, (-4-2)/2) = (1,-3)
Do the others in the same way.
Then use your distance formula to find the length of each median.
The length of the median from C to M(AB) is
√((1+5)^2 + (-3-6)^2) = √(36+81) = √117
M(AB) = (A+B)/2 = ((-3+5)/2, (-4-2)/2) = (1,-3)
Do the others in the same way.
Then use your distance formula to find the length of each median.
The length of the median from C to M(AB) is
√((1+5)^2 + (-3-6)^2) = √(36+81) = √117
henry2,
!. A(-3, -4), M(x, y), B(5, -2).
x + 3 = (5+3)/2,
X = 1.
y+4 = (-2+4)/2,
Y = -3.
B(5, -2), M(x, y), C(-5, 6).
x-5 = (-5-5)/2,
X = 0.
y+2 = (6+ 2)/2,
Y = 2.
A(-3, -4), M(x, y), C(-5, 6).
x + 3 = (5+3)/2,
X = 1.
y+4 = (-2+4)/2,
Y = -3.
B(5, -2), M(x, y), C(-5, 6).
x-5 = (-5-5)/2,
X = 0.
y+2 = (6+ 2)/2,
Y = 2.
A(-3, -4), M(x, y), C(-5, 6).
henry2,
2. M(1, -3), C(-5, 6).
(MC)^2 = (-5-1)^2 + (6+3) = 36 + 81 = 117,
MC = 10.8.
M(0, 2), A(-3, -4),
(MA)^2 = (-3-0)^2 + (-4-2)^2 = 9 + 36 = 45.
MA = 6.7.
M(x, y), B(5, -2).
(MC)^2 = (-5-1)^2 + (6+3) = 36 + 81 = 117,
MC = 10.8.
M(0, 2), A(-3, -4),
(MA)^2 = (-3-0)^2 + (-4-2)^2 = 9 + 36 = 45.
MA = 6.7.
M(x, y), B(5, -2).