Asked by DariaV

Three different size lights are running off a low voltage system. The resistance of the three lights are R1 =3 ohms, R2 = 9 ohms, and R3 = 9 ohms. They are all connected in parallel with a 5.0 V battery. The internal resistance of the battery is negligible.

What is the current through R1?
Answered by DariaV
I=R/V
1.67A? Right?
Answered by oobleck
correct. The entire 5V drop happens for each bulb, since they are in parallel.
Answered by henry2,
I = E/R = 5/3___Amps.
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