Asked by Nick
Using Vieta's formula, given
a+b+c =1
ab+bc+ac=-4
abc=-3
How do I find a+b, b+c and a+c?
a+b+c =1
ab+bc+ac=-4
abc=-3
How do I find a+b, b+c and a+c?
Answers
Answered by
oobleck
you could start by noting that
(a+b+c)^2 = 1^2
a^2 + b^2 + c^2 + 2(ab+ac+bc) = 1
a^2 + b^2 + c^2 = 9
Whatever you do, it ain't gonna be pretty.
(a+b+c)^2 = 1^2
a^2 + b^2 + c^2 + 2(ab+ac+bc) = 1
a^2 + b^2 + c^2 = 9
Whatever you do, it ain't gonna be pretty.
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