Asked by Nick
How do I find non-decimal solutions for the two following cubic equations ?
x^3-11x^2-4x-44=0
x^3+11x^2-4x+44=0
x^3-11x^2-4x-44=0
x^3+11x^2-4x+44=0
Answers
Answered by
henry2,
Your Eqs should be:
x^3 + 11x^2 - 4x - 44 = 0.
x^3 - 11x^2 - 4x + 44 = 0.
Add the Eqs:
2x^3 - 8x = 0, (sum).
x^3 - 4x = 0,
x(x^2 - 4) = 0,
x^2 - 4 = 0,
x^2 = 4,
X = 2 and -2.
x^3 + 11x^2 - 4x - 44 = 0.
x^3 - 11x^2 - 4x + 44 = 0.
Add the Eqs:
2x^3 - 8x = 0, (sum).
x^3 - 4x = 0,
x(x^2 - 4) = 0,
x^2 - 4 = 0,
x^2 = 4,
X = 2 and -2.
Answered by
scott
3rd order (cubic) equations should have 3 solutions
1st eqn ... factoring ... (x + 11)(x^2 - 4) = 0 ... x = -11 , ±2
2nd eqn ... factoring ... (x - 11)(x^2 - 4) = 0 ... x = 11 , ±2
1st eqn ... factoring ... (x + 11)(x^2 - 4) = 0 ... x = -11 , ±2
2nd eqn ... factoring ... (x - 11)(x^2 - 4) = 0 ... x = 11 , ±2
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